Swapping two numbers is a fundamental task in programming, and in this article, we will write a C# Program to Swap Two Numbers in various ways.
Table of Contents
Method 1: C# Program to Swap Two Numbers Using a Temporary Variable
One of the simplest ways to swap two numbers is by using a temporary variable.
This method involves three steps:
Storing the value of the first variable in the temporary variable, assigning the value of the second variable to the first, and finally, assigning the value stored in the temporary variable to the second variable.
// C# program to swap two numbers using a temporary variable
using System;
class Program
{
static void Main()
{
int num1 = 10, num2 = 20, temp;
// Displaying original values
Console.WriteLine($"Original Values: num1 = {num1}, num2 = {num2}");
// Swapping using a temporary variable
temp = num1;
num1 = num2;
num2 = temp;
// Displaying swapped values
Console.WriteLine($"Swapped Values: num1 = {num1}, num2 = {num2}");
}
}
Output:
Original Values: num1 = 10, num2 = 20
Swapped Values: num1 = 20, num2 = 10
Code Explanation:
In this method, we use a temporary variable (temp
) to store the value of num1
before assigning the value of num2
to it. This ensures that the original value of num1
is not lost during the swap.Â
Finally, we assign the temporary variable temp
value to the num2
variable to complete the swap.
Method 2: C# Program to swap two numbers without third variable
In the code example below, we will try to swap two numbers using arithmetic operations without a temporary variable.
using System;
class Program
{
static void Main()
{
// Declare and initialize two numbers
int num1 = 5, num2 = 10;
Console.WriteLine($"Before swapping: num1 = {num1}, num2 = {num2}");
// Swap without using a temporary variable
num1 = num1 + num2; // Now, num1 is 15 (5 + 10)
num2 = num1 - num2; // Now, num2 is 5 (15 - 10)
num1 = num1 - num2; // Now, num1 is 10 (15 - 5)
Console.WriteLine($"After swapping: num1 = {num1}, num2 = {num2}");
}
}
Output:
Before swapping: num1 = 5, num2 = 10
After swapping: num1 = 10, num2 = 5
Code Explanation:
- Step 1: Add num1 and num2 and store the result in num1. Now, num1 is 15 (5 + 10)
- Step 2: Subtract num2 from the num1 and store the result in num2. Now, num2 is 5 (15 – 10)
- Step 3: Subtract the num2 from the updated num1 and store the result in num1. Now, num1 is 10 (15 – 5)
Method 3: Program to Swap Two Numbers Using XOR Bitwise Operation
XOR bitwise operation is an efficient way to swap two numbers without using a temporary variable. Below is the code example.
// C# program to swap two numbers using XOR bitwise operation
using System;
class Program
{
static void Main()
{
int num1 = 10, num2 = 20;
// Displaying original values
Console.WriteLine($"Original Values: num1 = {num1}, num2 = {num2}");
// Swapping using XOR bitwise operation
num1 = num1 ^ num2;
num2 = num1 ^ num2;
num1 = num1 ^ num2;
// Displaying swapped values
Console.WriteLine($"Swapped Values: num1 = {num1}, num2 = {num2}");
}
}
Output:
Original Values: num1 = 10, num2 = 20
Swapped Values: num1 = 20, num2 = 10
Code Explanation:
- Initially,
num1
is 10, andnum2
is 20. - We print the values before swapping:
num1 = 10, num2 = 20
. - We then perform the swapping using XOR operations.
- Step 1:
num1
becomes the XOR of the original values ofnum1
andnum2
, so it becomes 30 (10 ^ 20). - Step 2:
num2
becomes the XOR of the updatednum1
and the originalnum2
, so it becomes 10 (30 ^ 20). - Step 3:
num1
becomes the XOR of the updatednum1
and the updatednum2
, so it becomes 20 (30 ^ 10). - We print the values after swapping:
num1 = 20, num2 = 10
.
Conclusion
In this article, we learned three different methods to write a C# Program to Swap Two Numbers.
Each method has its own merits, and the choice between them may depend on specific requirements or performance considerations. As a C# developer, these techniques will enhance your problem-solving skills and broaden your understanding of fundamental programming practice. Happy coding!
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